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Linux syntax error operand expected

log= $ ( who | grep $ 1 | cut - c 30- 31, 33- 34). And, time= $ ( date | cut - c 12- 13, 15- 16). Based on your comment, this would probably at least allow gdate to give you a better error message. / bin/ bash # define directory to search and current date DIRECTORY= " / *. xml" CURRENT_ DATE= $ ( date ' + % Y% m% d' ). Combination of ceving and Tomek' s: #! / bin/ bash read num1 num2 num3 while [ $ num1 - lt $ num3 ] do echo $ num1 num1= $ ( ( num1+ num2) ) done. Remove the spaces. Instead of saying: let LEFT= PWED - $ PWTIME. say: let LEFT = PWED- PWTIME. But this is brittle. Unless you know what you' re doing, you should use bash' s " Arithmetic Context" : ( ( LEFT = PWED.

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  • Video:Linux expected syntax

    Linux operand expected

    That' s because at some point $ { hitEnd[ k] } expands to nothing ( it is undefined). I get the same error with ( ( l< = ) ). You should write your for loop as: k= 0 for ( ( l= $ { & & l< = $ { hitEnd[ k] } ; l+ + ) ) ; do. Sorry, the problem was the color formatting. I added a second case " intranet - R" ( uppercase " R" ) without color formatting - works like a charm. Thank you for digging your heads in and sorry for bothering! You never set a value for a1, so the arithmetic statement ( ( $ a1> $ a2) ) expands to ( ( > ) ). Perhaps you meant a1= $ num1 instead of num1= $ a1, but you don' t need a1 at all; you can just use $ num1. The same holds for a2 and. The most likely explanation is that your bash version is too old to implement associative arrays, which might be the case if you are using the default version from OS X, for example. Get a definitive version for the running bash. Line 6 of your script expects arguments 1 to 5 to exist.

    If you run your script with no arguments $ 1+ $ 2+ $ 3+ $ 4+ $ 5 will becomewhich explains the error message. ( A similar explanation is valid for the second error. The error is in ( ( $ sum = $ 1 + $ 2) ) to add numbers in a bash script. Use arithmetic expansion: For Integer: sum= $ ( ( $ 1 + $ 2) ) sub= $ ( ( $ 1 - $ 2) ).